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the upward normal force exerted by the floor is 620 n on an elevator passenger who weighs 650 n.
The Upward Normal Force Exerted By The Floor Is 620 N On An Elevator ...
Oct 04, 2019 · There are two forces acting on the passenger on the elevator: - The upward normal force, R - The weight of the passenger, W. Therefore we can write Newton's second law as. where a is the acceleration of the passenger and m its mass. Here we took upward as positive direction, so that R is positive. The mass of the passenger can also be written as
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Sep 18, 2017 · Problem 1. (7 points): The upward normal force exerted by the floor is 620 N on an elevator passenger who weighs 650 N. Is the passenger accelerating? … If so, what are the magnitude and direction of the acceleration? (Take g = 9.8 m/s²)
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Solved The Upward Normal Force Exerted By The Floor Is 620 N - Chegg
The upward normal force exerted by the floor is 620 N on an elevator passenger who weighs 650 N. What is the magnitude of the acceleration? Question: The upward normal force exerted by the floor is 620 N on an elevator passenger who weighs 650 N. What is the magnitude of the acceleration?
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The upward normal force exerted by the floor is 620 N on an elevator passenger who weighs 650 N. What is the magnitude of the acceleration? Express your answer in meters per second squared. What is the direction of the acceleration? a = 0.45 m/s^2 downward.
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Solving these two equations simultaneously gives B = 8.00 N – A A2 + (8.00 N – A)2 = 33.99 N2 A2 + 64.00 N2 – 16.00 N A + A2 = 33.99 N2 The quadratic formula gives two solutions: A = 5.00 N and B = 3.00 N or A = 3.00 N and B = 5.00 N. In either case, the larger force has magnitude 5.00 N. (b) Let A = 5.00 N and B = 3.00 N, with the larger ...
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